Please do something about it already.

[Mhaeric]

"(23/24)^3" (or about 88%) are your chances of not-winning if everyone can roll on each chest. But because they can't

You must have missed the part where I explained how it's possible to win all 3 coffers and talked about how that actually plays out in reality. It was in the post with the table in it if you want to take a gander. If you don't, it boils down to me conceding the 7/8 value as being a more realistic one.

Thinking this all over... the thing is, you can do all this complex maths about your chances and how three separate rolls is different to one roll with three winners and your chances once you've rolled your number and you're waiting to see what everyone else got... but at the end of the day, 24 people walk into the raid and three come out with a coffer. Therefore you have a 1-in-8 chance that you will be one of them.

Yes, that's the probability of being a winner for a single run if you ignore what the rolls were. That's not being questioned. It does nothing, however, to describe what the probability of rolling poorly over the course of x runs has on the probability of not winning over those x runs. If they only had a handful of rolls in the 80's as their highest rolls, for example, it becomes much less surprising that they didn't win.