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  1. #1
    Player
    Sav's Avatar
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    Sav Alithos
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    Quote Originally Posted by Betelgeuzah View Post
    7.0 is only 2 away from 9.0 guyz.

    Run to the hills!
    But the hills have eyes!!

    Anyway, in all seriousness, Richter is a log-based scale, right? so a 9.0 is 100 times more...earthquake-y?...than a 7.0. I wouldn't be too worried.
    (3)

  2. #2
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    Betelgeuzah's Avatar
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    Captain Lalafist
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    Quote Originally Posted by Sav View Post
    But the hills have eyes!!

    Anyway, in all seriousness, Richter is a log-based scale, right? so a 9.0 is 100 times more...earthquake-y?...than a 7.0. I wouldn't be too worried.
    Not 100, 1000.

    Omigawd
    (0)

  3. #3
    Player
    Sav's Avatar
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    Quote Originally Posted by Betelgeuzah View Post
    Not 100, 1000.

    Omigawd
    10^9/10^7=10^(9-7)=10^2=cheeseburger
    (9)

  4. #4
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    Viridiana's Avatar
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    Aria Placida
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    Quote Originally Posted by Betelgeuzah View Post
    Not 100, 1000.

    Omigawd
    Quote Originally Posted by Sav View Post
    10^9/10^7=10^(9-7)=10^2=cheeseburger
    Depends. Are we talking about wave amplitudes, or actual energy released?

    From Wiki:

    Because of the logarithmic basis of the scale, each whole number increase in magnitude represents a tenfold increase in measured amplitude; in terms of energy, each whole number increase corresponds to an increase of about 31.6 times the amount of energy released, and each increase of 0.2 corresponds to a doubling of the energy released.
    (0)

  5. #5
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    Quote Originally Posted by Sav View Post
    10^9/10^7=10^(9-7)=10^2=cheeseburger
    I'm so putting that on my next calc exam!
    (2)
    =^.^=