No. That's not how probability calculations work. Look up Bernoulli-ProcessInteresting... so would that put the odds of a run where a player who ISN'T you getting BOTH Sands at roughly 1.5% x 7 (basically the odds of getting both, multiplied by the number of other players). Meaning someone should expect to see someone else get both sands in every one out of ten runs. I know my figure isn't exact I'm just doing rough estimates in my head.
I'll just take your word for it... how I came up with that number was take the 1.5% chance I was given for it to happen personally in one run above, and multiplied it roughly by the 7 other party members. But that was guesswork and I figured there might be a fallacy in that approach.


No, the probability is less than 25% Each sand is its own separate roll with a 1/8 chance or 12.5% The odds of receiving neither would be (7/8)^2 or 49/64 or 15/64 chance of receiving a sand and another 15/64 chance of receiving an oil. Same thing with UAT, but people only need 10 of those total.
The chance is 21,88% to receive EXACTLY 1 sand out of 2 and 23,44% to receive AT LEAST 1 sand
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