Results 1 to 10 of 132

Hybrid View

  1. #1
    Player
    Raenryong's Avatar
    Join Date
    Sep 2013
    Posts
    281
    Character
    Serefina Solfyre
    World
    Sargatanas
    Main Class
    Archer Lv 50
    Let n represent number of targets.

    I think your suggested rotation was

    Fire 3 > RS > Fire 2 x3 > Flare x3
    Total time (0 speed): 21s

    220 + (100 * 1.8 * 1.2 * n) * 3 + (260 * 1.8 * 1.2 * n) * 3 = 220 + 648n + 1684.8n potency

    Time adjustment: 214.72 + 632.448n + 1644.3648n (~2.4% slower => ~2.4% DPS loss) potency

    Fire 2 > Fire 2 > RS > Fire 2 > Fire 2 > Flare x3
    Total time (0 speed): 20.5s

    (100 * n) + (100 * 1.4 * n) + (100 * 1.6 * 1.2 * n) + (100 * 1.8 * 1.2 * n) + (260 * 1.8 * 1.2 * n) *3 = 648n + 1684.8n potency

    214.72 + 632.448n + 1644.3648n = 648n + 1684.8n
    214.72 = 55.9872n
    Equalisation point is therefore n = 3.835... (3dp)
    Therefore, if number of targets is four or higher, second rotation is optimal.
    (0)
    Last edited by Raenryong; 05-27-2014 at 07:31 AM.

Tags for this Thread