Quote:
for x from 0 to 150 do
> for y from 0.50 to 1.50 by 0.01 do
> S:=y*3.15*(51+8+x);
> T:=y*3.15*(52+39+12+x);
> U:=y*3.15*(51+25+11+x);
> if (S>= 463 and S <= 463+20 and T>= 614 and T<= 614+20 and U >=549 and U<= 560) then print(x,y,S,T,U);end if;
> end do; end do;
which checks which possible values for "x" (=the mod ) and "y" (=the ftp) match while x is an integer and y varies by steps of 0.01 (the damage must be greater than what I find, and smaller than that damage +20). The only matching values are x=76,y=1.09.